ABCD is a Rhombus. DPR and CBR are straight lines. Prove that: DP.CR=DC.PR
ABCD is a rhombus. DPR and CBR are straight lines. Prove that: DP.CR=DC.PR Solution: DP.CR=DC.PR Given ABCD is rhombus . DPR and CBR are straight lines.∴ AD||CR we need to…
In triangle ABC, AB > AC. | E is the mid-point of BC | and AD is perpendicular to BC
In triangle ABC, AB > AC. E is the mid-point of BC and AD is perpendicular to BC. Prove that AB2 + AC2 = 2.AE2 + 2.BE2 Solution:In ∆ ABD…
OP, OQ and OR are drawn perpendiculars to the sides BC, CA and AB of ∆ ABC |Prove that AR2 +BP2 +CQ2 = AQ 2 + CP 2+BR2
In the following figure, OP, OQ and OR are drawn perpendiculars to the sides BC, CA and AB respectively of triangle ABC. Prove that AR2 +BP2 +CQ2 = AQ 2…
AB = BC and AD is perpendicular to CD. Prove that AC2 = 2.BC. DC
Question:In the figure AB = BC and AD is perpendicular to CD. Prove that AC2 = 2.BC. DC solution :In ∆ ADC AC2 = AD2 + DC2 AC2 = AB2…
ABCD is a parallelogram | Prove that ∆ BCF and ∆ DFE are equal in area
ABCD is a parallelogram , a line trhough A cuts DC at oint F and BC produced at E Prove that ∆ BCF is equal in area to ∆ DFE.…
Geometry Sum | ABCD is a square. Prove in each case ∆APD ≅ ∆BPC | Find Angle DPC Angle PCD and Angle PCD |
ABCD is a square and APB is an equilateral triangle. Prove in each case: 1) 𢁪PD ≅ 𢁫PC 2) Find the angles of 𢁭PC Solution : First PartGiven �P…