ABCD is a rhombus. DPR and CBR are straight lines. Prove that: DP.CR=DC.PR Solution: DP.CR=DC.PR Given ABCD is rhombus . DPR and CBR are straight lines.∴ AD||CR we need to Prove : DP.CR=DC.PRIn ∆ ADP and ∆ PCRWe have : Read more
In triangle ABC, AB > AC. E is the mid-point of BC and AD is perpendicular to BC. Prove that AB2 + AC2 = 2.AE2 + 2.BE2 Solution:In ∆ ABD AB2 = AD 2 + BD 2 Or AB2 = Read more
In the following figure, OP, OQ and OR are drawn perpendiculars to the sides BC, CA and AB respectively of triangle ABC. Prove that AR2 +BP2 +CQ2 = AQ 2 + CP 2+BR2 solution : Construction : joinA-0, BO and Read more
Question:In the figure AB = BC and AD is perpendicular to CD. Prove that AC2 = 2.BC. DC solution :In ∆ ADC AC2 = AD2 + DC2 AC2 = AB2 – BD2 + DC2(AS ABD is a right angled triangle)or Read more
ABCD is a parallelogram , a line trhough A cuts DC at oint F and BC produced at E Prove that ∆ BCF is equal in area to ∆ DFE. Construction: AC is joined. AB || CD and AD || Read more
ABCD is a square and APB is an equilateral triangle. Prove in each case: 1) 𢁪PD ≅ 𢁫PC 2) Find the angles of 𢁭PC Solution : First PartGiven �P = Equilateral triangleR.T.P.1) 𢁪PD ≅ 𢁫PC 2) Find 𢈍PC, Read more
