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mc9cs_anglestriangles

AB = BC and AD is perpendicular to CD. Prove that AC2 = 2.BC. DC

ByUrooz Ali

Sep 2, 2015

Question:In the figure AB = BC and AD is perpendicular to CD. Prove that AC2 = 2.BC. DC

solution :In &#x2206 ADC
AC2 = AD2 + DC2
AC2 = AB2 – BD2 + DC2(AS ABD is a right angled triangle)
or AC2 = AB2 + DC2 – BD2
AC2 = AB2 + DC2 – ( DC-BC )2
or AC2 = AB2 + DC2 – (DC2 + BC 2 -2 DC. BC)
or AC2 = AB2 + DC2 – DC2 – BC 2 + 2 DC. BC
or AC2 = AB2 – AB 2 + 2 DC. BC (As AB = BC )
.’. AC2 = 2 DC. BC Proved

See also  In triangle ABC, AB > AC. | E is the mid-point of BC | and AD is perpendicular to BC

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ABCD is a parallelogram | Prove that &#x2206 BCF and &#x2206 DFE are equal in area
OP, OQ and OR are drawn perpendiculars to the sides BC, CA and AB of &#x2206 ABC |Prove that AR2 +BP2 +CQ2 = AQ 2 + CP 2+BR2

By Urooz Ali

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