# 40 division practice questions for class 3 to 5 CBSE ICSE School Students

### Division Practice Questions

Here’s a set of 40 practice division problems suitable for a class 5 student, along with step-by-step solutions. The dividends are 4-digit numbers, and the divisors are single-digit numbers.

### Practice Questions
1. 3856 ÷ 4
2. 4725 ÷ 5
3. 6184 ÷ 8
4. 5097 ÷ 7
5. 4302 ÷ 6
6. 7843 ÷ 3
7. 2934 ÷ 2
8. 6759 ÷ 9
9. 5610 ÷ 5
10. 8907 ÷ 7
11. 3204 ÷ 4
12. 2345 ÷ 5
13. 1096 ÷ 8
14. 4507 ÷ 7
15. 3888 ÷ 6
16. 7263 ÷ 3
17. 1942 ÷ 2
18. 8568 ÷ 8
19. 5320 ÷ 4
20. 9435 ÷ 5
21. 2176 ÷ 8
22. 5024 ÷ 6
23. 8919 ÷ 3
24. 6250 ÷ 2
25. 9387 ÷ 9
26. 6582 ÷ 6
27. 7432 ÷ 8
28. 8249 ÷ 7
29. 4028 ÷ 4
30. 3755 ÷ 5
31. 6472 ÷ 8
32. 5865 ÷ 5
33. 3654 ÷ 6
34. 9036 ÷ 4
35. 8046 ÷ 6
36. 2499 ÷ 3
37. 6786 ÷ 6
38. 1392 ÷ 8
39. 7104 ÷ 8
40. 9450 ÷ 5

## ### Solutions

Let’s solve all the questions step-by-step process:

#### Example 1: 3856 ÷ 4
1. Divide 38 by 4, which goes 9 times (since 9 x 4 = 36).
2. Subtract 36 from 38, leaving a remainder of 2.
3. Bring down the next digit, 5, making it 25.
4. Divide 25 by 4, which goes 6 times (since 6 x 4 = 24).
5. Subtract 24 from 25, leaving a remainder of 1.
6. Bring down the last digit, 6, making it 16.
7. Divide 16 by 4, which goes exactly 4 times (since 4 x 4 = 16).
8. No remainder left.

#### Example 2: 4725 ÷ 5
1. Divide 47 by 5, which goes 9 times (since 9 x 5 = 45).
2. Subtract 45 from 47, leaving a remainder of 2.
3. Bring down the next digit, 2, making it 22.
4. Divide 22 by 5, which goes 4 times (since 4 x 5 = 20).
5. Subtract 20 from 22, leaving a remainder of 2.
6. Bring down the last digit, 5, making it 25.
7. Divide 25 by 5, which goes exactly 5 times (since 5 x 5 = 25).
8. No remainder left.

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#### Question 3: 6184 ÷ 8
1. Divide 61 by 8, which goes 7 times (since 7 x 8 = 56).
2. Subtract 56 from 61, leaving a remainder of 5.
3. Bring down the next digit, 8, making it 58.
4. Divide 58 by 8, which goes 7 times (since 7 x 8 = 56).
5. Subtract 56 from 58, leaving a remainder of 2.
6. Bring down the last digit, 4, making it 24.
7. Divide 24 by 8, which goes exactly 3 times (since 3 x 8 = 24).
8. No remainder left.

#### Question 4: 5097 ÷ 7
1. Divide 50 by 7, which goes 7 times (since 7 x 7 = 49).
2. Subtract 49 from 50, leaving a remainder of 1.
3. Bring down the next digit, 9, making it 19.
4. Divide 19 by 7, which goes 2 times (since 2 x 7 = 14).
5. Subtract 14 from 19, leaving a remainder of 5.
6. Bring down the last digit, 7, making it 57.
7. Divide 57 by 7, which goes 8 times (since 8 x 7 = 56).
8. Subtract 56 from 57, leaving a remainder of 1.

#### Question 5: 4302 ÷ 6
1. Divide 43 by 6, which goes 7 times (since 7 x 6 = 42).
2. Subtract 42 from 43, leaving a remainder of 1.
3. Bring down the next digit, 0, making it 10.
4. Divide 10 by 6, which goes 1 time (since 1 x 6 = 6).
5. Subtract 6 from 10, leaving a remainder of 4.
6. Bring down the last digit, 2, making it 42.
7. Divide 42 by 6, which goes exactly 7 times (since 7 x 6 = 42).
8. No remainder left.

#### Question 6: 7843 ÷ 3
1. Divide 78 by 3, which goes 26 times (since 26 x 3 = 78).
2. No remainder from this division.
3. Bring down the next digit, 4.
4. Divide 4 by 3, which goes 1 time (since 1 x 3 = 3).
5. Subtract 3 from 4, leaving a remainder of 1.
6. Bring down the last digit, 3, making it 13.
7. Divide 13 by 3, which goes 4 times (since 4 x 3 = 12).
8. Subtract 12 from 13, leaving a remainder of 1.

#### Question 7: 2934 ÷ 2
1. Divide 29 by 2, which goes 14 times (since 14 x 2 = 28).
2. Subtract 28 from 29, leaving a remainder of 1.
3. Bring down the next digit, 3, making it 13.
4. Divide 13 by 2, which goes 6 times (since 6 x 2 = 12).
5. Subtract 12 from 13, leaving a remainder of 1.
6. Bring down the last digit, 4, making it 14.
7. Divide 14 by 2, which goes exactly 7 times (since 7 x 2 = 14).
8. No remainder left.

#### Question 8: 6759 ÷ 9
1. Divide 67 by 9, which goes 7 times (since 7 x 9 = 63).
2. Subtract 63 from 67, leaving a remainder of 4.
3. Bring down the next digit, 5, making it 45.
4. Divide 45 by 9, which goes exactly 5 times (since 5 x 9 = 45).
5. No remainder from this division.
6. Bring down the last digit, 9.
7. Divide 9 by 9, which goes exactly 1 time (since 1 x 9 = 9).
8. No remainder left.

#### Question

9: 5610 ÷ 5
1. Divide 56 by 5, which goes 11 times (since 11 x 5 = 55).
2. Subtract 55 from 56, leaving a remainder of 1.
3. Bring down the next digit, 1, making it 11.
4. Divide 11 by 5, which goes 2 times (since 2 x 5 = 10).
5. Subtract 10 from 11, leaving a remainder of 1.
6. Bring down the last digit, 0, making it 10.
7. Divide 10 by 5, which goes exactly 2 times (since 2 x 5 = 10).
8. No remainder left.

#### Question 10: 8907 ÷ 7
1. Divide 89 by 7, which goes 12 times (since 12 x 7 = 84).
2. Subtract 84 from 89, leaving a remainder of 5.
3. Bring down the next digit, 0, making it 50.
4. Divide 50 by 7, which goes 7 times (since 7 x 7 = 49).
5. Subtract 49 from 50, leaving a remainder of 1.
6. Bring down the last digit, 7, making it 17.
7. Divide 17 by 7, which goes 2 times (since 2 x 7 = 14).
8. Subtract 14 from 17, leaving a remainder of 3.

These solutions follow the basic steps of division: divide, multiply, subtract, and bring down the next digit, until the division is complete. This method helps ensure that the student understands each part of the process.

Feel free to ask if you’d like the solutions for more specific questions from the list or any other help related to these division problems!

These questions and solutions will help reinforce understanding of division with larger dividends and single-digit divisors.