Category: mc9cs_pythagorastheorem

Question: Diagonals of rhombus ABCD intersect each other at point O. Prove that OA2 + OC2= 2AD2 + BD2/2 Solution: In &#x2206 AODOA2 = AD2 – OD2 ————-Eqn (i) In &#x2206 OBCOC2 = BC2 – OB2 ————-Eqn (ii) Adding Eqn (i) & Eqn (ii) We get,OA2 + OC2 = AD2 – OD2 + BC2 –…