Diagonals of rhombus ABCD intersect each other at point O. Prove that OA2+ OC2=2AD2-BD2/2
Question: Diagonals of rhombus ABCD intersect each other at point O. Prove that OA2 + OC2= 2AD2 + BD2/2 Solution: In ∆ AODOA2 = AD2 – OD2 ————-Eqn (i) In ∆ OBCOC2 = BC2 – OB2 ————-Eqn (ii) Adding Eqn (i) & Eqn (ii) We get,OA2 + OC2 = AD2 – OD2 + BC2 – … Read more