Geometry Sum | ABCD is a square. Prove in each case ∆APD ≅ ∆BPC | Find Angle DPC Angle PCD and Angle PCD |

   ABCD is a square and APB is an equilateral triangle. Prove in each case:  1) &#x2206APD ≅ &#x2206BPC    2) Find the angles of &#x2206DPC Solution : First PartGiven &#x2206ABP = Equilateral triangleR.T.P.1) &#x2206APD ≅ &#x2206BPC    2) Find &#x2220DPC, &#x2220PDC and &#x2220PCD, Proof: In &#x2206APD and &#x2206BPC AP = BP | Same side of … Read more

Theorem | the angle subtended by an arc of a circle | at the centre is double the angle subtended by it at | any point on the remaining part of the circle

Theorem : A circle  with centre O in which AB subtends  &#x2220AOB at centre and angle &#x2220ACB at any point  on the remaining part of the circle. R.T.P. – &#x2220AOB =  2 x &#x2220ACB Solution : Construction: Join CO and produce CO to point D . 1. In ∆AOC, OC = OA || Radii of … Read more