In the following figure, OP, OQ and OR are drawn perpendiculars to the sides BC, CA and AB respectively of triangle ABC. Prove that AR2 +BP2 +CQ2 = AQ 2 + CP 2+BR2 solution : Construction : joinA-0, BO and CO . For ∆ OAR, we can write:AR2 = OA2 – OR2 —— Eqn. (I)For … Read more
Question: Diagonals of rhombus ABCD intersect each other at point O. Prove that OA2 + OC2= 2AD2 + BD2/2 Solution: In ∆ AODOA2 = AD2 – OD2 ————-Eqn (i) In ∆ OBCOC2 = BC2 – OB2 ————-Eqn (ii) Adding Eqn (i) & Eqn (ii) We get,OA2 + OC2 = AD2 – OD2 + BC2 – … Read more
Question:In the figure AB = BC and AD is perpendicular to CD. Prove that AC2 = 2.BC. DC solution :In ∆ ADC AC2 = AD2 + DC2 AC2 = AB2 – BD2 + DC2(AS ABD is a right angled triangle)or AC2 = AB2 + DC2 – BD2 AC2 = AB2 + DC2 – ( DC-BC … Read more
ABCD is a parallelogram , a line trhough A cuts DC at oint F and BC produced at E Prove that ∆ BCF is equal in area to ∆ DFE. Construction: AC is joined. AB || CD and AD || BC .Now ∆ ACE and ∆ DCE are on the same base CE and between … Read more
Question 1:What did the traveler see in the desert ? Answer 1: The traveler from the ancient land saw a broken statue in the desert . There he saw two large and trunkless legs of stone standing in the desert. Near them on the sand was the face of the statue half – sunk in … Read more
गर्म गर्मी के बाद हम बरसात के दिन का लिए इंतजार करते हैं । बारिश का मौसम जून के महीने से शुरू होता है और अगस्त तक जारी रहता है। बारिश की पहली बौछार दिन के गर्म धूप को धो देता है और बेचैन कर देने वाली गर्मी से राहत देता है बारिश के दिन … Read more
Students need not rush from shop to shop at last time of evening for school photographs project work. Click on this image , print it and cut into pieces to use it. That is all. Relax and concentrate on your study.
The photographs has been joined on page . it doesn’t need to collect individual image. It is one step print. The image can be saved and can be print on one page. Then it can be cut out for pasting at various places.
First Photograph. Second Photograph. Third Photograph.